Question

D)16X+5-3=-2X-15 E)-X+40=4X F)6(X+5)=X G)5(y-9)-3=-18-y H)10-6(Z-8)=9+Z I)12+2N=9(N-7)-2Me ajudem que estou precisando ate de maiss por favor ajudem eu... E muito urgente

Answer 1

d)16x+5-3=-2x
16x+2x=-5+3
18x=-2
x=18/-2
x=-9
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e)-x+40=4x
-x-4x=-40
-5x=-40
x=-40/-5
x=-8
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f)6(x+5)=x
6x+30=x
6x-x=-30
5x=-30
x=-30/5
x=-6
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g)5(y-9)-3=-18-y
5y-45=-18-y
5y+y=45-18
6y=27
y=27/6
y=4,5
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h)10-6(z-8)=9+z
10-6z+48=9+z
-6z-z=-48+9-10
-7z=47
z=47/-7
z=-6,7
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i)12+2n=9(n-7)-2
2n=9n-63-2-12
9n-2n=49
7n=49
n=49/7
n=7

Answer 2

$d) \\ \\ 16x+5-3=-2x-15 \\ \\ 16x + 5 - 3 + 2x + 15 = 0 \\ \\ 18x +17 \\ \\ 18x = -17 \\ \\ x = -\frac{17}{18} \\ \\ e) \\ \\ -x+40=4x \\ \\ -x + 40 - 4x = 0 \\ \\ -5x + 40 = 0 (-1) \\ \\ 5x - 40 = 0 \\ \\ 5x = 40 \\ \\ x = \frac{40}{5} \\ \\ x = 8 \\ \\ f) \\ \\ 6(x+5)=x \\ \\ 6x + 30 = x \\ \\ 6x + 30 - x = 0 \\ \\ 5x = -30 \\ \\ x = \frac{-30}{5} \\ \\ x = -6$

$g) \\ \\ 5(y-9)-3=-18-y \\ \\ 5y - 45 - 3 +18 + y = 0 \\ \\ 6y -30 = 0 \\ \\ 6y = 30 \\ \\ y = \frac{30}{6} \\ \\ y = 5 \\ \\ h) \\ \\ 10 - 6(z-8)=9+z \\ \\ 10 - 6x +48 -9 - z = 0 \\ \\ -7z + 49 = 0 (-1) \\ \\ 7z - 49 \\ \\ 7z = -49 \\ \\ z = \frac{-49}{7} \\ \\ z = - 7$

$i) \\ \\ 12+2n=9(n-7)-2 \\ \\ 12 + 2n = 9n - 63 - 2\\ \\ 12 + 2n - 9n + 65=0 \\ \\ -7n + 77 = 0(-1)\\ \\ 7n-77 =0 \\ \\7n = 77 =0 \\ \\ n = \frac{77}{7} \\ \\ n = 11$