cual es la formula de 2x²-9x+4=0
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Fórmula de Bhaskara
2x² - 9x + 4 = 0
x = 9 + - √81 - 32
-------------------
4
x = 9 + - √49
---------------
4
x' = 9 + 7
--------
4
x' = 4
x" = 9 - 7
--------
4
x" = 1/2 S = ( 4 ; 1/2 )
2x² - 9x + 4 = 0
x = 9 + - √81 - 32
-------------------
4
x = 9 + - √49
---------------
4
x' = 9 + 7
--------
4
x' = 4
x" = 9 - 7
--------
4
x" = 1/2 S = ( 4 ; 1/2 )
Respondido por
0
2x² - 9x + 4 = 0
a = 2
b = -9
c = 4
Δ = b² -4 .a . c
Δ = (-9)² -4 . 2 . 4
Δ = 81 - 8 . 4
Δ = 81 - 32
Δ = 49

a = 2
b = -9
c = 4
Δ = b² -4 .a . c
Δ = (-9)² -4 . 2 . 4
Δ = 81 - 8 . 4
Δ = 81 - 32
Δ = 49
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