coordenadas do vértice da parábola f(x)=x²+3x-1=
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Boa tarde!
Solução!
![f(x)= x^{2} +3x-1\\\\\\
V\left ( \dfrac{b}{-2a}, \dfrac{\Delta}{-4a} \right )\\\\\\
a=1\\\\
b=3\\\\\
c=-1](https://tex.z-dn.net/?f=f%28x%29%3D+x%5E%7B2%7D+%2B3x-1%5C%5C%5C%5C%5C%5C%0AV%5Cleft+%28+%5Cdfrac%7Bb%7D%7B-2a%7D%2C+%5Cdfrac%7B%5CDelta%7D%7B-4a%7D++%5Cright+%29%5C%5C%5C%5C%5C%5C%0Aa%3D1%5C%5C%5C%5C%0Ab%3D3%5C%5C%5C%5C%5C%0Ac%3D-1 "f(x)= x^{2} +3x-1\\\\\\
V\left ( \dfrac{b}{-2a}, \dfrac{\Delta}{-4a} \right )\\\\\\
a=1\\\\
b=3\\\\\
c=-1")
![x_{V}= \dfrac{3}{-2.1}\\\\\\\\
x_{V}= \dfrac{3}{-2}\\\\\\\\
\boxed{ x_{V}=-\dfrac{3}{2}}\\\\\\\\\\\\
y_{V}= \dfrac{3^{2}-4.1.-1 }{-4.1}\\\\\\\
y_{V}= \dfrac{9+4 }{-4}\\\\\\\
\boxed{y_{V}= -\dfrac{13}{4}}\\\\\\\\\\
V\left (- \dfrac{3}{2} , -\dfrac{13}{4} \right )](https://tex.z-dn.net/?f=++x_%7BV%7D%3D+%5Cdfrac%7B3%7D%7B-2.1%7D%5C%5C%5C%5C%5C%5C%5C%5C%0A++x_%7BV%7D%3D+%5Cdfrac%7B3%7D%7B-2%7D%5C%5C%5C%5C%5C%5C%5C%5C%0A%0A+++%5Cboxed%7B+x_%7BV%7D%3D-%5Cdfrac%7B3%7D%7B2%7D%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C+%0Ay_%7BV%7D%3D+%5Cdfrac%7B3%5E%7B2%7D-4.1.-1+%7D%7B-4.1%7D%5C%5C%5C%5C%5C%5C%5C%0Ay_%7BV%7D%3D+%5Cdfrac%7B9%2B4+%7D%7B-4%7D%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7By_%7BV%7D%3D+-%5Cdfrac%7B13%7D%7B4%7D%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A%0A%0AV%5Cleft+%28-+%5Cdfrac%7B3%7D%7B2%7D+%2C+-%5Cdfrac%7B13%7D%7B4%7D+%5Cright+%29+++ "x_{V}= \dfrac{3}{-2.1}\\\\\\\\
x_{V}= \dfrac{3}{-2}\\\\\\\\
\boxed{ x_{V}=-\dfrac{3}{2}}\\\\\\\\\\\\
y_{V}= \dfrac{3^{2}-4.1.-1 }{-4.1}\\\\\\\
y_{V}= \dfrac{9+4 }{-4}\\\\\\\
\boxed{y_{V}= -\dfrac{13}{4}}\\\\\\\\\\
V\left (- \dfrac{3}{2} , -\dfrac{13}{4} \right )")
Boa tarde!
Bons estudos!
Solução!
Boa tarde!
Bons estudos!
complicated:
Obg!!
Dê nada!
Respondido por
1
f (x) = x² + 3x - 1
a = 1; b = 3; c = -1
Δ = b² - 4ac
Δ = 3² - 4 . 1 . (-1)
Δ = 9 + 4
Δ = 13
Vértice de x: Vértice de y:
Xv = - b / 2a Yv = - Δ / 4a
Xv = - 3 / 2 . 1 Yv = - 13 / 4 . 1
Xv = - 3 / 2 Yv = - 13 / 4
Xv = -1,5 Yv = -3,25
Como (x, y), as coordenadas do vértice são: V (-1.5 , -3.25).
Espero ter ajudado. Valeu!
a = 1; b = 3; c = -1
Δ = b² - 4ac
Δ = 3² - 4 . 1 . (-1)
Δ = 9 + 4
Δ = 13
Vértice de x: Vértice de y:
Xv = - b / 2a Yv = - Δ / 4a
Xv = - 3 / 2 . 1 Yv = - 13 / 4 . 1
Xv = - 3 / 2 Yv = - 13 / 4
Xv = -1,5 Yv = -3,25
Como (x, y), as coordenadas do vértice são: V (-1.5 , -3.25).
Espero ter ajudado. Valeu!
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