Question

coordenadas de vértice

y=-x²-3x

f(x)=x²-4

Answer 1

y= -x²-3x
a=-1
b=-3
c=0
Δ=b²-4ac
Δ=(-3)²-4(-1)(0)
Δ=9

$Xv= \frac{-b}{2a} = \frac{-(-3)}{-2} = \frac{3}{-2} =- \frac{3}{2} \\ \\ Yv= \frac{-delta}{4a} = \frac{-9}{-4}= \frac{9}{4} \\ \\ \\ V(- \frac{3}{2} , \frac{9}{4} )$


f(x)=x²-4
a=1
b=0
c=-4
Δ=b²-4ac
Δ=0²-4(-4)
Δ=16

$Xv= \frac{-b}{2a} = \frac{0}{2} =0 \\ \\ Yv= \frac{-delta}{4a} =- \frac{16}{4} =-4 \\ \\ V(0,-4)$