Question

converter as temperaturas em kelvinl(K)
a)10°c b)45°F​

Answer 1

Olá, Boa tarde, vamos lá!

$tk = 10c + 273 \\ tk = 283k \\ \\ \frac{tk - 273}{5} = \frac{tf - 32}{ 9} \\ \frac{tk - 273}{5} = \frac{45 - 32}{9} \\ \frac{tk - 273}{5} = \frac{13}{9} \\ \frac{tk - 273}{5} = 1.4 \\ tk - 273 = 7 \\ tk = 273 + 7 \\ tk = 280k$

conclusão: celsio\kelvin= 283
fahrenheit\kelvin= 280

Answer 2

k=°c+273
k=10+273
k=283

$\frac{k - 273}{5} = \frac{f - 32}{9}$

$9(k - 273) = 5(45 - 32) \\ 9k - 2457 = 5(13)$

$9k = 2457 + 65 \\ k = \frac{2522}{9}$

k=280,2