Question

conta resolvida por favor x² + 8x + 16

Answer 1

$Retirando~informacoes: \\\\ x^2 + 8x + 16 = 0\\ ax^2 + bx + c = 0 \\\\ a = 1 \\ b = 8 \\ c = 16 \\\\ Resolvendo: \\\\ \Delta = b^2 -4.a.c \\ \Delta = 8^2 - 4.1.16 \\ \Delta = 64- 64 \\ \Delta = 0 \\\\ x^+ = \frac{-b + \sqrt{\Delta}}{2.a}\\\\ x^+ = \frac{-8 + \sqrt{0} }{2.1}\\\\ x^+ = \frac{-8+0}{2} \qquad \qquad\qquad x^-= \frac{-8 - 0}{2} \\\\ x^+ = \frac{-8}{2} \qquad \qquad\qquad~~~ x^-= \frac{-8}{2} \\\\ x^+ = -4 \qquad \qquad\qquad~~~ x^- = -4$


Resposta extra, resolvendo por fatoração:

$x^2 + 8x + 16 = 0 \\\\ (x + a)^2 = x^2 + 2ax + a^2 \\\\ Resolucao: \\\\ a^2 = 16\\ a = 4 \\ \\ (x + 4)^2 = 0 \\ x + 4 = 0 \\ x = -4$

Answer 2

Delta:8 ao quadrado -4×1×16
Delta: 64-64
Delta:0
-8+-raiz quadrada de 0/ 2 ×1
8+-0/2
x1: 8+0/2 x2: 8-0/2
x1: 8/2 x2: 8/2
x1:4 x2: 4
Os valores de x: (4;4)