Question

conta da questão: y=x2-7x+10

Answer 1

y = x² - 7x + 10
0 = x² - 7x + 10

x² - 7x + 10 = 0
a = 1; b = - 7; c = 10

Δ = b² - 4ac
Δ = (-7)² - 4.1.10
Δ = 49 - 40
Δ = 9

x = - b +/- √Δ  = - (-7) +/- √9
          2a                2.1

x = 7 + 3 = 10/2 = 5
        2

x = 7 - 3  = 4/2 = 2
         2

R.: x = 2 e x = 5

Answer 2

Zeros da Função: 

$y=x^2-7x+10$

$a=1;b=-7;c=10\\\\\\ \Delta=b^2-4ac\to \Delta=(-7)^2-4*1*10\to \Delta=49-40\to \Delta=9\\\\ x' \neq x''\\\\\\ x= \frac{-b\pm \sqrt{\Delta} }{2a} \to x= \frac{-(-7)\pm \sqrt{9} }{2*1} \to x= \frac{7\pm 3 }{2} \to \\\\\\ x'= \frac{7+3 }{2} \to x'= \frac{10 }{2} \to x'=5\\\\\\ x''= \frac{7-3 }{2} \to x''= \frac{4 }{2} \to x''=2\\\\\\\\ S= \left \{2;5\left \}$