Question

Construir a matriz B = [bij] 3x3 tal que (bij) = i . J + i + j

Answer 1

B11= 1.1+1+1=3
B12=1.2+1+2=5
B13=1.3+1+3=7
B21=2.1+2+1=5
B22=2.2+2+2=8
B23=2.3+2+3=11
B31=3.1+3+1=7
B32=3.2+3+2=11
B33=3.3+3+3=15

(3 5 7    )
(5 8 11   )
(7 11 15 )