Matemática, perguntado por samanthasoares, 1 ano atrás

Construir a matriz A= (aij)4x2 onde aij=2i² +3j-10

Soluções para a tarefa

Respondido por Celio
0

Olá, Samantha.

 

<var>A= (a_{ij})_{4\times2},\text{ onde }a_{ij}=2i^2 +3j-10\\\\ a_{11}=2+3-10=-5\\\\ a_{12}=2+6-10=-2\\\\ a_{21}=8+3-10=1\\\\ a_{22}=8+6-10=4\\\\ a_{31}=18+3-10=11\\\\ a_{32}=18+6-10=14\\\\ a_{41}=32+3-10=25\\\\ a_{42}=32+6-10=28\\\\\\ \therefore A=\left[\begin{array}{cc}-5&amp;-2\\1&amp;4\\11&amp;14\\25&amp;28\end{array}\right]</var>

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