Matemática, perguntado por WandeilsonFC, 6 meses atrás

Construa a matriz B= (bij)3 x 2 tal que bij = -2i + 3j

Soluções para a tarefa

Respondido por CyberKirito
2

\Large\boxed{\begin{array}{l}\sf B=\begin{bmatrix}\sf b_{11}&\sf b_{12}\\\sf b_{21}&\sf b_{22}\\\sf b_{31}&\sf b_{32}\end{bmatrix}\\\sf b_{11}=-2\cdot1+3\cdot1=-2+3=1\\\sf b_{12}=-2\cdot1+3\cdot2=-2+6=4\\\sf b_{21}=-2\cdot2+3\cdot1=-4+3=-1\\\sf b_{22}=-2\cdot2+3\cdot2=-4+6=2\\\sf b_{31}=-2\cdot3+3\cdot1=-6+3=-3\\\sf b_{32}=-2\cdot3+3\cdot2=-6+6=0\\\underline{\rm A~matriz~pedida~\acute e}\\\\\sf B=\begin{bmatrix}\sf1&\sf4\\\sf-1&\sf2\\\sf-3&\sf0\end{bmatrix}\end{array}}

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