Question

construa a matriz B=(bij) 3×3/bij=i+j​

Answer 1

Olá leticialima27lima!

Veja a explicação:

$\large \sf \left[\begin{array}{ccc} \sf b_{11}& \sf b_{12}& \sf b_{13}\\ \sf b_{21}&\sf b_{22}& \sf b_{23}\\\sf b_{31}&\sf b_{32}& \sf b_{33}\end{array}\right]}$

Creio que seja, tal que:

$\large { \boxed {\sf bij =i+j }}$

Logo:

$\begin{array}{l}\begin{cases}\sf b_{11} = (1+1) = 2 ~~~\\\sf b_{12} =(1+2) = 3~~~~ \\ \sf b_{13} = (1+3) = 4~~~~\\ \sf b_{21} = (2+1) = 3~~~~\\ \sf b_{22} = (2+2) = 4~~~~\\ \sf b_{23} = (2+3) = 5~~~~\\ \sf b_{31} = (3+1) = 4~~~~\\ \sf b_{32} = (3+2) = 5 ~~~~\\ \sf b_{33}= (3+3) = 6 \end{cases}\\\\\end{array}$

Portanto mantém:

$\boxed { \boxed { \large { \left[\begin{array}{ccc}2&3&4\\3&4&5\\4&5&6\end{array}\right] \longrightarrow 3 \times 3 } } }$

✍️Att. MatiasHP