Question

Construa a matriz A de ordem 3 definida por:

A=[aij]3x3 » se i=j aij=i+j. Se i≠j aij=2i

Answer 1

$\large\boxed{\begin{array}{l}\sf A=\begin{bmatrix}\sf a_{11}&\sf a_{12}&\sf a_{13}\\\sf a_{21}&\sf a_{22}&\sf a_{23}\\\sf a_{31}&\sf a_{32}&\sf a_{33}\end{bmatrix}\\\sf a_{11}= 1+1=2~~a_{12}=2\cdot1=2~~a_{13}=2\cdot1=2\\\sf a_{21}=2\cdot2=4~~ a_{22}=2+2=4~~a_{23}=2\cdot2=4\\\sf a_{31}=2\cdot3=6~~a_{32}=2\cdot3=6~~a_{33}=3+3=6\\\\\sf A=\begin{bmatrix}\sf2&\sf2&\sf2\\\sf4&\sf4&\sf4\\\sf6&\sf6&\sf6\end{bmatrix}\end{array}}$

Answer 2

Resposta:

[2 2 2]

[4 4 4]

[6 6 6]

Explicação passo a passo:

3 x 3

3 linhas 3 colunas

a11 a12 a13

a21 a22 a23

a31 a32 a33

I = j

Aij = i + j

I diferente de j: aij = 2i

a11 = 1+1 = 2

i = j

a12 = 2.1 = 2

2.i

a13 = 2.1 = 2

2.i

a21 = 2.2 = 4

2.i

a22 = 2+2 = 4

i = j

a23 = 2.2 = 4

2.i

a31 = 2.3 = 6

2.i

a32 = 2.3 = 6

2.i

a33 = 3+3 = 6

2.i

R.:

[2 2 2]

[4 4 4]

[6 6 6]