Matemática, perguntado por AnaNguyen16, 1 ano atrás

Construa a matriz A=(aij)5×3, tal que aij=2i-3j

Soluções para a tarefa

Respondido por antoniosbarroso2011
2

A resolução encontra-se na imagem em anexo. Espero ter ajudado

Anexos:
Respondido por guilhermeRL
3

Boa noite!

\begin{bmatrix}a11&a12&a13\\a21&a22&a23\\a31&a32&a33\\a41&a42&a43\\a51&a52&a53\\\end{bmatrix}



\mathrm{a11}\Rightarrow\textup{2}\times\textup{1-3}\times\textup{1}\Rightarrow\textup{2-3}=\boxed{-1}

\mathrm{a12}\Rightarrow\textup{2}\times\textup{1-3}\times\textup{2}\Rightarrow\textup{2-6}=\boxed{-4}

\mathrm{a13}\Rightarrow\textup{2}\times\textup{1-3}\times\textup{3}\Rightarrow\textup{2-9}=\boxed{-7}

\mathrm{a21}\Rightarrow\textup{2}\times\textup{2-3}\times\textup{1}\Rightarrow\textup{4-3}=\boxed{1}

\mathrm{a22}\Rightarrow\textup{2}\times\textup{2-3}\times\textup{2}\Rightarrow\textup{4-6}=\boxed{-2}

\mathrm{a23}\Rightarrow\textup{2}\times\textup{2-3}\times\textup{3}\Rightarrow\textup{4-9}=\boxed{-5}

\mathrm{a31}\Rightarrow\textup{2}\times\textup{3-3}\times\textup{1}\Rightarrow\textup{6-3}=\boxed{3}

\mathrm{a32}\Rightarrow\textup{2}\times\textup{3-3}\times\textup{2}\Rightarrow\textup{6-6}=\boxed{0}

\mathrm{a33}\Rightarrow\textup{2}\times\textup{3-3}\times\textup{3}\Rightarrow\textup{6-9}=\boxed{-3}

\mathrm{a41}\Rightarrow\textup{2}\times\textup{4-3}\times\textup{1}\Rightarrow\textup{8-3}=\boxed{5}

\mathrm{a42}\Rightarrow\textup{2}\times\textup{4-3}\times\textup{2}\Rightarrow\textup{8-6}=\boxed{2}

\mathrm{a43}\Rightarrow\textup{2}\times\textup{4-3}\times\textup{3}\Rightarrow\textup{8-9}=\boxed{-1}

\mathrm{a51}\Rightarrow\textup{2}\times\textup{5-3}\times\textup{1}\Rightarrow\textup{10-3}=\boxed{7}

\mathrm{a52}\Rightarrow\textup{2}\times\textup{5-3}\times\textup{2}\Rightarrow\textup{10-6}=\boxed{4}

\mathrm{a53}\Rightarrow\textup{2}\times\textup{5-3}\times\textup{3}\Rightarrow\textup{10-9}=\boxed{1}



Matriz Resposta:

\begin{bmatrix}-1&-4&-7\\1&-2&-5\\3&0&-3\\5&2&-1\\7&4&1\\\end{bmatrix}



Att;Guilherme Lima


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