Question

construa a matriz a=(Aij)3×2 de modo que Aij=4i^2-2j​

Answer 1

Resposta:

Explicação passo a passo:

Observe que como é 3x2 temos

a11=4i²-2j​=4*1-2=2

a12=4i²-2j​=4*1-4=0

a21=4i²-2j​=4*4-2=14

a22=4i²-2j​=4*4-4=12

a31=4i²-2j​=4*9-2=34

a32=4i²-2j​=4*9-4=32

Logo, $\left[\begin{array}{cc}2&0\\14&12\\34&32\end{array}\right]$

Answer 2

Resposta:

Explicação passo a passo:

$A(3X2)$

$A=\left[\begin{array}{ccc}a_{11} &a_{12} \\a_{21} &a_{22} \\a_{31} &a_{32} \end{array}\right]$

$a_{ij} =4i^{2}-2j$

$a_{11}=4\:.(1)^{2} -2.(1)=4\:.\:1-2=4-2=2$

$a_{12}=4\:.(1)^{2} -2.(2)=4\:.\:1-4=4-4=0$

$a_{21}=4\:.(2)^{2} -2.(1)=4\:.\:4-2=16-2=14$

$a_{22}=4\:.(2)^{2} -2.(2)=4\:.\:4-4=16-4=12$

$a_{31}=4\:.(3)^{2} -2.(1)=4\:.\:9-2=36-2=34$

$a_{32}=4\:.(3)^{2} -2.(2)=4\:.\:9-4=36-4=32$

$Portanto...$

$A=\left[\begin{array}{ccc}2 &0} \\14} &12} \\14} &32} \end{array}\right]$

$Espero\:ter\:ajudado!$