Question

Considere os logaritmos log 3 = 0.477, log 4 = 0.602 elog 5 = 0,6
logaritmos, determine o valor de log=12.

Answer 1

$log(12) = log(3 \times 4) = \\ log(3) + log(4) = 0.477 + 0.602 = \\ 1.079$