Question

Considere o triangulo ABC com :A= 45°,a=4 e b=4√ 2. determine o lado c.

Answer 1

a² = b² + c² - 2cos 45º bc

16 = 32 + c² - 2 √2/2 * 4√2 * c

16 = 32 + c² - 8c

c² - 8c  + 16 = 0

delta  = 0 

c = -b ± √delta / 2a 

c = 4

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09/03/2016
Sepauto - SSRC
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