Question

Considere na figura que t1 = 15s, v1 = 6m/s, t2 = 23s e v2 = 30m/s. Calcule a aceleração do móvel em m/s2.

A) 4
B) 5
C) 8
D) 3
E) 24

Answer 1

$t_1=15s\\v_1=6m/s\\t_2=23s\\v_2=30m/s\\\\a = \frac{\Delta v}{\Delta t} = \frac{v_2-v_1}{t_2-t_1} = \frac{30-6}{23-15}=\frac{24}{8}=3m/s^2$