Question

considere log 2=A log 5=b , calcule


a) log 10
b)log 50
c)log 40
d)log 80
e)log 200
d)log(2 ³.5² )

Answer 1

 log 2=A log 5=b

a) log 10 = log(2.5) = log2 + log 5 = a + b

b)log 50 = log(2.5²) = log2 + 2log 5 = a + 2b

c)log 40 = log(2³.5) = 3log2 + log 5 = 3a + b

d)log 80 = log(2^4.5) = 4log2 + log 5 = 4a + b

e)log 200 = log(2³.5²) = 3log2 + 2log 5 = 3a + 2b

d)log(2³.5² ) = 3log2 + 2log 5 = 3a + 2b