Question

Considere f(x)=2ax+b, f(2)=7 e f(1)=1, calcule o valor de f(10)

Answer 1

Resposta:

$55$

Explicação passo-a-passo:

$f(x) = 2ax + b$

$f(2) = 7$  $f(1) = 1$

$\begin{cases}4a + b = 7\\2a + b = 1\end{cases}$

$\mathsf{2-2b + b = 7}\\\mathsf{b = -5}\\\mathsf{2a - 5 = 1}\\\mathsf{2a = 6}\\\mathsf{a = 3}$

$f(10) = 2.3.10 - 5 = 55$