Question

Considere a P.A. a seguir: (2x -3, x+ 1, 3x + 5). Determine
o valor de x:

Answer 1

$a_{1}=2x-3$

$a_{2}=x+1$

$a_{3}=3x+5$

$r=a_{2}-a_{1} \\ r=a_{3}-a_{2}→a_{2}-a_{1}=a_{3}-a_{2}$

$(3x+5)-(2x-3)=(3x+5)-(x+1)$

$3x-5-2x+3=3x+5-x-1 \\\cancel{3x} -2x-\cancel{3x}=5-1+5-3$

$-2x=6\times(-1)$

$2x=-6 \\x=-\frac{6}{2}$

$\boxed{\boxed{x=-3}}$