Considere a função f (X)= x² + bx + 3 encontre os valores de A e B para cada caso a seguir:
1 e 3 são os zeros da função
-1 e -3 são os zeros da função
Soluções para a tarefa
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Boa noite!
Solução!
![f(x)= x^{2} +bx+3\\\\\\
x_{1}=1\\\\\\
x_{2}=3\\\\
Fazendo!\\\\\\
(x-x_{1})\times(x-x_{2})\\\\\\
(x-1)\times(x-3)\\\\\\
( x^{2} -3x-x+3)\\\\\\
( x^{2} -4x+3)\\\\\
\boxed{a=1~~~~
b=-4}](https://tex.z-dn.net/?f=f%28x%29%3D+x%5E%7B2%7D+%2Bbx%2B3%5C%5C%5C%5C%5C%5C%0Ax_%7B1%7D%3D1%5C%5C%5C%5C%5C%5C%0A+x_%7B2%7D%3D3%5C%5C%5C%5C+%0AFazendo%21%5C%5C%5C%5C%5C%5C%0A%28x-x_%7B1%7D%29%5Ctimes%28x-x_%7B2%7D%29%5C%5C%5C%5C%5C%5C%0A%28x-1%29%5Ctimes%28x-3%29%5C%5C%5C%5C%5C%5C%0A%28+x%5E%7B2%7D+-3x-x%2B3%29%5C%5C%5C%5C%5C%5C%0A%28+x%5E%7B2%7D+-4x%2B3%29%5C%5C%5C%5C%5C%0A%5Cboxed%7Ba%3D1%7E%7E%7E%7E%0Ab%3D-4%7D%0A "f(x)= x^{2} +bx+3\\\\\\
x_{1}=1\\\\\\
x_{2}=3\\\\
Fazendo!\\\\\\
(x-x_{1})\times(x-x_{2})\\\\\\
(x-1)\times(x-3)\\\\\\
( x^{2} -3x-x+3)\\\\\\
( x^{2} -4x+3)\\\\\
\boxed{a=1~~~~
b=-4}")
Mesmo raciocínio!
![x_{1}=-1\\\\\\ x_{2}=-3\\\\\\\
(x-x_{1})\times(x-x_{2})\\\\\\
(x-(-1))\times(x-(-3))\\\\\\
(x+1)\times(x+3)\\\\\\
( x^{2} +3x+x+3)\\\\\\\
( x^{2} +4x+3)\\\\\\\
\boxed{a=1~~~b=4}](https://tex.z-dn.net/?f=x_%7B1%7D%3D-1%5C%5C%5C%5C%5C%5C+x_%7B2%7D%3D-3%5C%5C%5C%5C%5C%5C%5C%0A%28x-x_%7B1%7D%29%5Ctimes%28x-x_%7B2%7D%29%5C%5C%5C%5C%5C%5C%0A%28x-%28-1%29%29%5Ctimes%28x-%28-3%29%29%5C%5C%5C%5C%5C%5C%0A%28x%2B1%29%5Ctimes%28x%2B3%29%5C%5C%5C%5C%5C%5C%0A%28+x%5E%7B2%7D+%2B3x%2Bx%2B3%29%5C%5C%5C%5C%5C%5C%5C%0A%28+x%5E%7B2%7D+%2B4x%2B3%29%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7Ba%3D1%7E%7E%7Eb%3D4%7D "x_{1}=-1\\\\\\ x_{2}=-3\\\\\\\
(x-x_{1})\times(x-x_{2})\\\\\\
(x-(-1))\times(x-(-3))\\\\\\
(x+1)\times(x+3)\\\\\\
( x^{2} +3x+x+3)\\\\\\\
( x^{2} +4x+3)\\\\\\\
\boxed{a=1~~~b=4}")
Boa noite!
Bons estudos!
Solução!
Mesmo raciocínio!
Boa noite!
Bons estudos!
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