Question

considere a função de f (x)=3x²-4x+5

a) f(-2)=

b) f (0)=

Answer 1

$a)f( - 2) = 3 \times {( - 2)}^{2} - 4 \times ( - 2) + 5 = 3 \times 4 + 8 + 5 = 12 + 8 + 5 = 25 \\ b)f(0) = 3 \times {0}^{2} - 4 \times 0 + 5 = 3 \times 0 - 0 + 5 = 5$