Question

Considerando x = (3^-1+6^-¹)/√(1+9.16-¹) e y = (3^-2+2^-1)/∛(1-7.2^-3), os valores de x e y são respectivamente:

a)2/5 e 11/9
b)2/45 e 11/25
c)2/5 e 8/11
d)5/8 e 11/36
e)8/5 e 36/11

Answer 1

x = (3-¹ + 6-¹) /√ 1 + 9 . 16-¹
x = (1/3 + 1/6) / √ 1 + 9 . 1/16
x = (2/6 + 1/6) / √ 1 + 9/16
x = 3/6 / √ 16/16 + 9/16
x = 3/6 / √ 25/16
x = 3/6 / 5/4
x = 3/6 . 4/5
x = 12/30 : 6
x = 2/5

y = 3-² + 2-¹ / ³√ 1^-7 . 2-³
y = 1/9 + 1/2 / ³√ 1/1 . 1/2³
y = 2/18 + 9/18 / ³√1/2³
y = 11/18 / 1/2
y = 11/18 . 2/1
y = 22/18 : 2
y = 11/9
Letra A