Question

considerando que Log 2= 0,3010 e Log3= 0,4771
calcule o logaritmo: log√12

Answer 1

Resolve usando propriedades dos logaritmos.
log V12=log 12^1/2=1/2 log 12=1/2 (log 4.3)=1/2 (log4 +log3)=1/2 (log 2^2+log3)=1/2 (2 log 2 + log 3)=
=1/2 (2.0,301+0,4771)=1/2 (0,6020+0,4771)=1/2.1,0791=
=1,0791/2=0,53955...resposta.