Question

considerando que a equação

Answer 1

Resposta:

Letra C

Explicação passo-a-passo:

$p+q=\frac{-b}{a}\\pq=\frac{c}{a} \\\\a=6\\b=1\\c=-1\\\\p+q=\frac{-1}{6} \\\\pq=\frac{-1}{6}\\\\ \frac{1}{p}+\frac{1}{q}=\frac{q+p}{pq} = \frac{-1}{6}:\frac{-1}{6}=1$