Question

Considerando os polinômios
b= 2x3 – 6x2 – 9x + 10 C = x3 + 7x2 + 9x + 20.

calcule
b-c

Answer 1

Resposta:

b= 2x³ – 6x² – 9x + 10      C = x³ + 7x² + 9x + 20

b-c = (2x³-x³)  ( - 6x²-7x²)  (-9x-9x) +10 -20

b-c = x³ -13x² -18x -10

Answer 2

Resposta:

b = 2x ^ 3 - 6x ^ 2 - 9x + 10 C = x ^ 3 + 7x ^ 2 + 9x

b = 2x ^ 3 - 6x ^ 2 - 9x + 10 C = x ^ 3 + 7x ^ 2 + 9x+ 20

b = 2x ^ 3 - 6x ^ 2 - 9x + 10 C = x ^ 3 + 7x ^ 2 + 9x+ 20b - c = (2x ^ 3 - x ^ 3)(- 6x ^ 2 - 7x ^ 2) * (- 9x - 9x) + 10 - 2

b = 2x ^ 3 - 6x ^ 2 - 9x + 10 C = x ^ 3 + 7x ^ 2 + 9x+ 20b - c = (2x ^ 3 - x ^ 3)(- 6x ^ 2 - 7x ^ 2) * (- 9x - 9x) + 10 - 2b - c = x ^ 3 - 13x ^ 2 - 18x - 10