Question

Considerando o seguinte valor para x:

$x = {3}^{2} + \sqrt[3]{64} \div {8}^{ \frac{1}{3} } - \frac{4}{5} \div 2 + {4}^{0}$
Então x vale:

a) 49/5
b) 49/2
c) 58/5
d) 1
e) 0



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Answer 1

Resposta:

$x = 3 {}^{2} + \sqrt[3]{64} \div 8 {}^{ \frac{1}{3} } - \frac{4}{5} \div 2 + 4 {}^{0}$

$x = 9 + \frac{ \sqrt[3]{64} }{ \sqrt[3]{8} } - \frac{4}{10} + 1$

$x = 9 + \sqrt[3]{8} - \frac{4}{10} + 1$

$x = 10 - \frac{4}{10} + \sqrt[3]{8}$

$x = \frac{96}{10} + \sqrt[3]{8}$

$x = \frac{96}{10} + 2$

$x = \frac{116}{10}$

$x = \frac{58}{5}$

Answer 2

Resposta:

Explicação passo-a-passo:

$3^2+\sqrt[3]{64}\div 8^{\frac{1}{3}}-\frac{4}{5}\div2 +4^0\\9+\sqrt[3]{2^6}\div \sqrt[3]{2^3}-\frac{4}{5}\times \frac{1}{2} +1\\9+2^{\frac{6}{3}}\div 2^{\frac{3}{3}}-\frac{4}{10} +1\\9+2^2\div 2^1-\frac{2}{5} +1\\9+\frac{4}{2}-\frac{2}{5} +1\\9+2-\frac{2}{5}+1\\12-\frac{2}{5}\\\\\frac{60-2}{5}=\boxed{\frac{58}{5}}$

Espero ter sido útil.\\\\