Question

considerando log2= 0,3010 e log3= 0,4771, calcule:

a) log5
b)log32

Answer 1

a)

$log5\\\\log\frac{10}{2}\\\\log10-log2\\\\1-0,3010\\\\0,6990$

b)

$log32\\\\log2^5\\\\5.log2\\\\5\;.\;0,3010\\\\1,505$