Question

considerando log2=0,3, log3=0,5 e log5=0,7, determine o valor de:
d) log1,2

e) (log1,5)^2

f) log raiz quadrada de 0,3

Answer 1

d)
log1,2=log12/10
log12-log10=
log4+log3-1=
log2² +log3-1=
2log2+log3-1=
2(0,3) +0,5-1=
0,6+0,5-1=
1,1-1=-0,5

e)
log(1,5)²=
2log15/10=
2log15-log10=
2(log3+log5)-1=
2(0,5+0,7)-1
1+1,4-1=1,4

f)
log√0,3=

$( \frac{3}{10} )^{ \frac{1}{2} }$

$\frac{1}{2} log \frac{3}{10} =$

$\frac{1}{2} (log3-log10)$

$\frac{1}{2} (o,5-1)=$

$\frac{1}{2}(-0,5)=-0,25$