Question

considerando log 3=0,0477 e log 5=0,699 calcule:
1) log 15
2) log 45
3)log 3/5
4)log 0,6​

Answer 1

Resposta:

a) log(15) = log(3*5) = log(3) + log(5) = 0.477 + 0.699 = 1.176

b) log(45) = log(3*15) = log(3) + log(15) = 0.477 +1.176 = 1.653

c) log(5/3) = log(5) - log(3) = 0.699 - 0.477 = 0.222

d) log(0.6) = log(6/10) = log(2) + log(3) - 1 = 0.301 + 0.477 - 1 = -0.222

e) log(20) = log(2) + log(10) = 1 + 0.301 = 1.301

f) log2(25) = lgg2(5^2) = 2log2(5) = 2*2.322 = 4.644 

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Explicação passo-a-passo: