Question

considerando log 2 = 0 3010 e log 3 = 0 4771 calcule log 750

Answer 1

Resposta:

750 =3*5²*2*5 =2*3*5³

log 750 =log (2*3*5³) =log 2 +log 3 + log 5³

=log 2 + log 3 + 3 * log 5

******log 5 =log10/2 =log 10 -log 2 =1 -log 2

=log 2 + log 3 + 3 * (1-log 2)

=log 2 + log 3 +3 -3*log2

log 3 +3 - 2*log 2

=0,4771 +3 -2*0,3010 = 2,8751

Answer 2

Log 750

= Log 2 * 3 * 5³

= Log 2 + Log 3 + 3 Log 5

= 0,3010 + 0,4771 + 3*(0,6989)

= 0,3010 + 0,4771 + 2,0967

= 2,8748