Question

considerando log 2=0,3010 e log 3=0,4771 calcule: log 72, log raiz quadrada, log 200, log 8 e log de raiz cubica de 60

Answer 1

log 2=0,3010 e log 3=0,4771

log 72 = log(2³.3²) ==> 2log2 + 2log3 ==> 2.(0,3010)+2.(0,4471)

0,6020+0,8942 ==> 1,4962
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log √y = logy^1/2 ==> 1logy
                                       2
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log 200 = log ( 2³.5²) ==> 3log2 + 2log10/2 ==> 3log2 +2(log10 - log2)

 3log2 + 2.1 - 2log2 ==>  3log2 + 2 - 2log2 ==> log2 + 2 

0,3010 + 2 ==> 2,3010
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log 8 = log 2³ ==> 3log2 ==> 3.(0,3010) ==> 0,9030
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log ∛60 = log 60^1/3 ==> 1 log(2².3.5) ==> 1( 2log2 + log3 + 2log10/2
                                                    3               3

2log2 + log3 + 2(log10 - log2) ==> 2log2 + log3 + 2log10 - 2log2)

log3 + 2.1 ==> 0,4771 +2 ==> 2,4771