Question

Considerando log 2 = 0,3010 e log 3 = 0,4771, calcule log 3,6.

Answer 1

$log_{} 3,6=log_{} \frac{36}{10} =log_{} 36-log_{} 10=log_{} (4.9)-1=log_{} ( 2^{2} . 3^{2} )-1$$=log_{} 2^{2} +log_{} 3^{2} -1=2.log_{} 2 +2.log_{} 3} -1$$=2.(0,3010)+2.(0,4771)-1=0,602+0,9542-1=0,5562$

Answer 2

log2=0,3010
log 3=0,4771
3,6 => 3,6.5 
3,6=Log 18/Log 5
Log 18 = Log (6.3) =>
Log(6)=Log(2.3)
Log 2 + Log 3=0,7781
======================
Log(6.3)=Log18
0,7781+0,4771=1,2552 (Log 18)
Log 18/Log 5 =>
Log 10/Log 2 = Log 5 =>
1-0,3010=0,699
Log 18/Log 5 = Log 3,6
1,2552-0,699=0,5562 ///
Log (3,6)=0,5562