Question

considerando as funçoes g(x)= 2x -4 e h(x)= 3x+1/2x


A) h(g(x))

Answer 1

g(x) = 2x - 4
h(x) = $\frac{3x + 1}{2x}$

h(g(x)) = h(2x - 4) 

2($\frac{3x + 1}{2x}$) - 4

$\frac{6x + 2}{2x} - 4$

mmc = 2x

6x + 2 - 8x
6x - 8x = -2
-2x = -2 (*-1)
2x = 2
x = 2/2
x = 1

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