Question

considerando as aproximações log 2 = 0,3 e log 3 = 0,48, calcule: log da raiz de 24

Answer 1

$log \sqrt{24} = log \sqrt{4.6} = log 2 \sqrt{2.3} =log ( 2. 2^{ \frac{1}{2}} 3^{ \frac{1}{2}}) = log 2 + \frac{1}{2} log 2 + \frac{1}{2} log3=$$0,3 + \frac{1}{2}.0,3+ \frac{1}{2}.0,48=0,3 + 0,15 + 0,24=0,69$