Question

Conplicada dado Seno de alfa 3/5 calcule a) cosseno de alfa b ) tangente de alfa

Answer 1

use as identidades$cos^2 = 1-sen^2 \\ cos^2 = 1- (\frac{3}{5})^2 = 1- \frac{9}{25} = \frac{16}{25} \\ cos= \sqrt\frac{ {16}}{ {25}} \\ cos= \frac{4}{5}$


$tangente = \frac{sen}{cos} =$


$\frac{3/5}{4/5}} = \frac{3}{5} * \frac{5}{4} = \frac{3}{4}$