Question

conjunto soluçao de x²-2x+1=0 e( 9x-5)(x+6)=0 me ajuda genteeeeeeee

Answer 1

$x^2-2x+1=0\\\frac{-b}{a}=x'+x''\\\frac{c}{a}=x'x''\\x'=1\\x''=1$
S{xer/x=1} (É uma raiz dupla )

$(9x-5)(x+6)=0\\9x^2+49x+30=0\\Delta=b^2-4ac=1321\\x=\frac{-49+ \sqrt{1321} }{18}\\x"=\frac{-49- \sqrt{1321} }{18}$