Question

Conjunto de verdade X2+5×+6=0

Answer 1

x²+5x+6=0
a:1 b:5 c:6
∆=b²-4.a.c
∆=5²-4.1.6
∆=25-24
∆=1

-x+-√∆/2.a
-5+-1/2

x¹= -5-1/2
x¹= -6/2
x¹= -3

x²= -5+1/2
x²= -4/2
x²= -2

S= {(-3,-2)}

Answer 2

x² + 5x + 6 = 0

Δ = b² - 4*a*c

Δ = 25 - 4*1*6

Δ = 25 - 24

Δ = 1

√Δ = 1

x' = - b + √Δ/2*a

x' = -5 + 1/2

x' = - 4/2 = - 2

x" = - b - √Δ/2*a

x" = - 5 - 1 /2

x" = - 6/2 = - 3

S = { -2, -3 }

bons estudos