Question

conjugado do número complexo
z=(3-i).(2+2*^2/3+i

Answer 1

Boa tarde!!!

z = (3-i)(2+2i)² / 3+i

z = (3-i)(3-i)(2+2i)² / (3+i)(3-i)

z = (3-i)(3-i)(2+2i)² / (9+1)

z = (3-6i-1)(4+8i-4) / (9+1)

z = (2-6i)(8i) / (10)

z =(16i+48)/10

z =24/5 +8i/5

conjugado de z=24/5-8i/5

Bons estudos