Question

COMPLETE AS TABELAS, COMO SE FAZ ISSO? PFV ​

Answer 1

Resposta:

Explicação passo-a-passo:

$3^4=81\\3^3=27\\3^2=9\\3^1=3\\3^0=1\\3^{-1}=\frac{1}{3}\\\\3^{-2}=\frac{1}{9}\\\\3^{-3}=\frac{1}{27}\\\\3^{-4}=\frac{1}{81}$

$(\frac{2}{5})^4=\frac{16}{625}\\\\(\frac{2}{5})^3=\frac{8}{125}\\\\(\frac{2}{5})^2=\frac{4}{25}\\\\(\frac{2}{5})^1=\frac{2}{5}\\\\(\frac{2}{5})^0=1\\\\(\frac{2}{5})^{-1}=\frac{5}{2}\\\\(\frac{2}{5})^{-2}=\frac{25}{4}\\\\(\frac{2}{5})^{-3}=\frac{125}{8}\\\\(\frac{2}{5})^{-4}=\frac{625}{16}$

pelo que entendi é isso.