Matemática, perguntado por raissav640, 9 meses atrás

complete a tabela seguir
opção A

× y=(×)= [×,f(×)]
0
1/2
1
2
3

Soluções para a tarefa

Respondido por arthurfranchilongen
0

× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3× y=(×)= [×,f(×)]

0

1/2

1

2

3

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