Matemática, perguntado por EvelinUzumaki, 4 meses atrás

Complete a figura a seguir com números, sabendo que o número correspondente a cada retângulo resulta da adição dos números dos dois retângulos que o sustentam.

Anexos:

Soluções para a tarefa

Respondido por Atoshiki
4

Após completar a figura, o resultado foi:

\LARGE\begin {array}{c c c c c c c c}\cline{4-5}&&&\multicolumn{2}{|c|}{~~0,9~}&&&&\cline{3-6}&&\multicolumn{2}{|c|}{-0,9}&\multicolumn{2}{|c|}{~~1,8~}&&\\\cline{2-7}~~&\multicolumn{2}{|c|}{-2,5}&\multicolumn{2}{|c|}{~~1,6~~}&\multicolumn{2}{|c|}{~~0,2~}&\\\cline{1-8}\multicolumn{2}{|c|}{-2,4}&\multicolumn{2}{|c|}{-0,1}&\multicolumn{2}{|c|}{~~1,7~}&\multicolumn{2}{|c|}{-1,5}\\\cline{1-8}\end {array}

Acompanhe a solução:

Conforme orientação, a soma dos dois retângulos da base tem como resultado o retângulo de cima.

Cálculo:

Calculando passo a passo.

>>> 1º cálculo:

\LARGE\begin {array}{c c c c c c c c}\cline{4-5}~~~~&&&\multicolumn{2}{|c|}{~~~~~~~}&&&&\cline{3-6}&&\multicolumn{2}{|c|}{~~~~~~~}&\multicolumn{2}{|c|}{~~~~~~~}&&\\\cline{2-7}~~&\multicolumn{2}{|c|}{-2,5}&\multicolumn{2}{|c|}{~~~~~~~}&\multicolumn{2}{|c|}{~~~~~~~}&\\\cline{1-8}\multicolumn{2}{|c|}{~~~~?~~~}&\multicolumn{2}{|c|}{-0,1}&\multicolumn{2}{|c|}{~~~~~~~}&\multicolumn{2}{|c|}{~~~~~~~}\\\cline{1-8}\end {array}

\large\begin {array}{l}?+(-0,1)=-2,5\\\\?-0,1=-2,5\\\\?=-2,5+0,1\\\\\Large\boxed{\boxed{?=-2,4}}\Huge\checkmark\end {array}

>>> 2º cálculo:

\large\begin {array}{l}-\dfrac{3}{2}=-3\div2=\Large\boxed{\boxed{-1,5}}\end {array}

\LARGE\begin {array}{c c c c c c c c}\cline{4-5}&&&\multicolumn{2}{|c|}{~~~~~~~}&&&&\cline{3-6}&&\multicolumn{2}{|c|}{~~~~~~~}&\multicolumn{2}{|c|}{~~~~~~~}&&\\\cline{2-7}~~&\multicolumn{2}{|c|}{-2,5}&\multicolumn{2}{|c|}{~~~~~~~}&\multicolumn{2}{|c|}{~~0,2~}&\\\cline{1-8}\multicolumn{2}{|c|}{-2,4}&\multicolumn{2}{|c|}{-0,1}&\multicolumn{2}{|c|}{~~~?~~~}&\multicolumn{2}{|c|}{-1,5}\\\cline{1-8}\end {array}

\large\begin {array}{l}?+(-1,5)=0,2\\\\?-1,5=0,2\\\\?=0,2+1,5\\\\\Large\boxed{\boxed{?=1,7}}\Huge\checkmark\end {array}

>>> 3º cálculo:

\LARGE\begin {array}{c c c c c c c c}\cline{4-5}&&&\multicolumn{2}{|c|}{~~~~~~~}&&&&\cline{3-6}&&\multicolumn{2}{|c|}{~~~~~~~}&\multicolumn{2}{|c|}{~~~~~~~}&&\\\cline{2-7}~~&\multicolumn{2}{|c|}{-2,5}&\multicolumn{2}{|c|}{~~~?~~~}&\multicolumn{2}{|c|}{~~0,2~}&\\\cline{1-8}\multicolumn{2}{|c|}{-2,4}&\multicolumn{2}{|c|}{-0,1}&\multicolumn{2}{|c|}{~~1,7~}&\multicolumn{2}{|c|}{-1,5}\\\cline{1-8}\end {array}

\large\begin {array}{l}-0,1+1,7=?\\\\\Large\boxed{\boxed{?=1,6}}\Huge\checkmark\end {array}

>>> 4º cálculo:

\LARGE\begin {array}{c c c c c c c c}\cline{4-5}&&&\multicolumn{2}{|c|}{~~~~~~~}&&&&\cline{3-6}&&\multicolumn{2}{|c|}{~~~?~~~}&\multicolumn{2}{|c|}{~~~~~~~}&&\\\cline{2-7}~~&\multicolumn{2}{|c|}{-2,5}&\multicolumn{2}{|c|}{~~1,6~~}&\multicolumn{2}{|c|}{~~0,2~}&\\\cline{1-8}\multicolumn{2}{|c|}{-2,4}&\multicolumn{2}{|c|}{-0,1}&\multicolumn{2}{|c|}{~~1,7~}&\multicolumn{2}{|c|}{-1,5}\\\cline{1-8}\end {array}

\large\begin {array}{l}-2,5+1,6=?\\\\\Large\boxed{\boxed{?=-0,9}}\Huge\checkmark\end {array}

>>> 5º cálculo:

\LARGE\begin {array}{c c c c c c c c}\cline{4-5}&&&\multicolumn{2}{|c|}{~~~~~~~}&&&&\cline{3-6}&&\multicolumn{2}{|c|}{-0,9}&\multicolumn{2}{|c|}{~~~?~~~}&&\\\cline{2-7}~~&\multicolumn{2}{|c|}{-2,5}&\multicolumn{2}{|c|}{~~1,6~~}&\multicolumn{2}{|c|}{~~0,2~}&\\\cline{1-8}\multicolumn{2}{|c|}{-2,4}&\multicolumn{2}{|c|}{-0,1}&\multicolumn{2}{|c|}{~~1,7~}&\multicolumn{2}{|c|}{-1,5}\\\cline{1-8}\end {array}

\large\begin {array}{l}1,6+0,2=?\\\\\Large\boxed{\boxed{?=1,8}}\Huge\checkmark\end {array}

>>> 6º cálculo:

\LARGE\begin {array}{c c c c c c c c}\cline{4-5}&&&\multicolumn{2}{|c|}{~~~?~~~}&&&&\cline{3-6}&&\multicolumn{2}{|c|}{-0,9}&\multicolumn{2}{|c|}{~~1,8~}&&\\\cline{2-7}~~&\multicolumn{2}{|c|}{-2,5}&\multicolumn{2}{|c|}{~~1,6~~}&\multicolumn{2}{|c|}{~~0,2~}&\\\cline{1-8}\multicolumn{2}{|c|}{-2,4}&\multicolumn{2}{|c|}{-0,1}&\multicolumn{2}{|c|}{~~1,7~}&\multicolumn{2}{|c|}{-1,5}\\\cline{1-8}\end {array}

\large\begin {array}{l}-0,9+1,8=?\\\\\Large\boxed{\boxed{?=0,9}}\Huge\checkmark\end {array}

Resposta:

Portanto,

\LARGE\begin {array}{c c c c c c c c}\cline{4-5}&&&\multicolumn{2}{|c|}{~~0,9~}&&&&\cline{3-6}&&\multicolumn{2}{|c|}{-0,9}&\multicolumn{2}{|c|}{~~1,8~}&&\\\cline{2-7}~~&\multicolumn{2}{|c|}{-2,5}&\multicolumn{2}{|c|}{~~1,6~~}&\multicolumn{2}{|c|}{~~0,2~}&\\\cline{1-8}\multicolumn{2}{|c|}{-2,4}&\multicolumn{2}{|c|}{-0,1}&\multicolumn{2}{|c|}{~~1,7~}&\multicolumn{2}{|c|}{-1,5}\\\cline{1-8}\end {array}

Se quiser saber mais, acesse:

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Bons estudos!

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