Question

Como se resolve x2-8x+12=0

Answer 1

x² - 8x + 12 = 0

A= 1

B= - 8

C= 12

∆= b² - 4ac

∆= ( - 8)² - 4 • 1 • 12

∆= 64 - 48

∆= 16

x= - b ± √∆ / 2a

x= - ( - 8) ± √16 / 2 • 1

x= 8 ± 4/2

x'= 8 + 4/2 = 12/2 = 6

x''= 8 - 4/2 = 4/2 = 2

S= ( 6 , 2)