Question

como se resolve a equações:
x+3/2+x+2/3=12
2x²-15=3
4x²-36x=0

Answer 1

x+3/2+x+2/3=12
x + x = 12 - 3/2 - 2/3
2x =59/6
x = 59/6 / 2
x = 59/6 * 1/2
x = 59 / 12

2x²-15=3
2x² = 3 +15
2x² = 18
x² = 18 /2
x² = 9
x = 3

4x²-36x=0
x (4x - 36) = 0
x = 0
4x - 36 = 0
4x = 36
x = 36/4
x = 9

Answer 2

a)
$x+ \frac{3}{2} +x+ \frac{2}{3} =12 \\ \\ mmc(2,3)=6 \\ \\ 6x+9+6x+4=72 \\ 12x=72-13 \\ 12x=59 \\ \\ x= \frac{59}{12}$

b)
$2 x^{2} -15=3 \\ 2 x^{2} =3+15 \\ 2 x^{2} =18 \\ x^{2} =18\div2 \\ x^{2} =9 \\ x=\pm \sqrt{9} \\ x=\pm3$

c)
$4 x^{2} -36x=0 \\ 4x(x-9)=0 \\ \\ 4x=0 \\ x=0 \\ \\ x-9=0 \\ x=9$