Question

como se resolve a equação exponencial 3 elevado a x - 5 = 27 elevado a 1-x

Answer 1

$Resolu\c{c}\~ao \to \left\{\begin{array}{ccc}3^{x-5} = 27^{1-x}\\\\3^{x-5} = (3^3)^{1-x}\\\\3^{x-5} = 3^{3-3x}\\\\x-5 = 3-3x\\\\x+3x = 3+5\\\\4x = 8\\\\\boxed{\boxed{x = \frac{8}{4} = 2}} \end{array}\right$

Espero ter ajudado. :))