Question

como se resolve 4x(x+3)+9=0​

Answer 1

$4 {x}^{2} + 12x + 9 = 0 \\ x = \frac{ - (12) + - \sqrt{ {12}^{2}- 4(4)(9)} }{2(4)} \\ x = \frac{ - 12 + - \sqrt{144-144} }{8} = \frac{ - 12 + \sqrt{0} }{8} \\ x = \frac{ -12}{8}= -\frac{3}{2}$