Question

Como se resolve?
1) -X²-5-4=0 2) -X²+5x+6=0

Answer 1

Resposta:

Utilizando a formulá de Bhaskara

Explicação passo a passo:

Primeiro identifique os termos A,B e C.

1)

A= -1     B=0    C= -9

Δ$=b^{2} - 4 .a. c$

Δ$= (0)^{2} - 4 . (-1). (-9)$

Δ$= 0 - 36$

Δ=36

$x = \frac{-b\frac{+}{} \sqrt{delta} }{2.a}\\\\x = \frac{-0\frac{+}{}\sqrt{36} }{2.(-1)} \\\\\\x'=\frac{-0+6}{-2} \\\\x''= -3\\\\\\\\x''=\frac{-0-6}{-2} \\\\x''= 3$

Logo após usar a formulá de x, encontre X linha 1 e 2.

2)

A= -1      B= 5        C= 6

Δ$=(5)^{2} -4.(-1).6$

Δ$= 25 + 24$

Δ$= 49$

$x =\frac{ -(5)\frac{+}{} \sqrt{49} }{2.(-1)} \\\\x = \frac{-5\frac{+}{} 7}{-2}\\ \\\\\\x' = \frac{-5+7}{-2} \\\\x'= \frac{2}{-2} \\\\x'= -1\\\\\\\\x''= \frac{-5-7}{-2} \\\\x'' = \frac{-12}{-2} \\\\x''= 6$