Como se desenvolve ??
Anexos:
lucasalves98:
a imagem não dar pra ver direito o indice mais essa raiz é raiz cubica de 16 no é???
Exatamente raiz cubica de 16
Soluções para a tarefa
Respondido por
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Boa Noite!
![(\frac{(0,5)^{-2}.2 ^{0,333...}. \sqrt[3]{16}}{( 0,125)^{-3} })= \\ \\ ( \frac{( \frac{5}{10}) ^{-2}.2 ^{ \frac{1}{3} }.16 ^{ \frac{1}{3} }}{ (\frac{125}{1000}) ^{-3}})=\\ \\ ( \frac{( \frac{1}{2}) ^{-2}.2 ^{ \frac{1}{3} }.2 ^{ \frac{4}{3} }}{ (\frac{1}{8}) ^{-3}})=\\ \\ ( \frac{ 2 ^{2}.2 ^{ \frac{1}{3} }.2 ^{ \frac{4}{3} }}{ 8 ^{3}})=\\ \\ ( \frac{ 2 ^{2+ \frac{1}{3} + \frac{4}{3} }}{ 2 ^{9}})=\\ \\ ( \frac{ 2 ^{ \frac{11}{3}}}{ 2 ^{9}})=\\ \\ 2 ^{ \frac{11}{3}-9}}= \\ \\ 2^{ -\frac{16}{3} }](https://tex.z-dn.net/?f=+%28%5Cfrac%7B%280%2C5%29%5E%7B-2%7D.2+%5E%7B0%2C333...%7D.+%5Csqrt%5B3%5D%7B16%7D%7D%7B%28+0%2C125%29%5E%7B-3%7D+%7D%29%3D+%5C%5C++%5C%5C+%28+%5Cfrac%7B%28+%5Cfrac%7B5%7D%7B10%7D%29+%5E%7B-2%7D.2+%5E%7B+%5Cfrac%7B1%7D%7B3%7D+%7D.16+%5E%7B+%5Cfrac%7B1%7D%7B3%7D+%7D%7D%7B+%28%5Cfrac%7B125%7D%7B1000%7D%29+%5E%7B-3%7D%7D%29%3D%5C%5C++%5C%5C+%28+%5Cfrac%7B%28+%5Cfrac%7B1%7D%7B2%7D%29+%5E%7B-2%7D.2+%5E%7B+%5Cfrac%7B1%7D%7B3%7D+%7D.2+%5E%7B+%5Cfrac%7B4%7D%7B3%7D+%7D%7D%7B+%28%5Cfrac%7B1%7D%7B8%7D%29+%5E%7B-3%7D%7D%29%3D%5C%5C++%5C%5C+%28+%5Cfrac%7B+2+%5E%7B2%7D.2+%5E%7B+%5Cfrac%7B1%7D%7B3%7D+%7D.2+%5E%7B+%5Cfrac%7B4%7D%7B3%7D+%7D%7D%7B+8+%5E%7B3%7D%7D%29%3D%5C%5C++%5C%5C+%28+%5Cfrac%7B+2+%5E%7B2%2B+%5Cfrac%7B1%7D%7B3%7D++%2B+%5Cfrac%7B4%7D%7B3%7D+%7D%7D%7B+2+%5E%7B9%7D%7D%29%3D%5C%5C++%5C%5C+%28+%5Cfrac%7B+2+%5E%7B+%5Cfrac%7B11%7D%7B3%7D%7D%7D%7B+2+%5E%7B9%7D%7D%29%3D%5C%5C++%5C%5C++2+%5E%7B+%5Cfrac%7B11%7D%7B3%7D-9%7D%7D%3D+%5C%5C++%5C%5C++2%5E%7B+-%5Cfrac%7B16%7D%7B3%7D+%7D++ "(\frac{(0,5)^{-2}.2 ^{0,333...}. \sqrt[3]{16}}{( 0,125)^{-3} })= \\ \\ ( \frac{( \frac{5}{10}) ^{-2}.2 ^{ \frac{1}{3} }.16 ^{ \frac{1}{3} }}{ (\frac{125}{1000}) ^{-3}})=\\ \\ ( \frac{( \frac{1}{2}) ^{-2}.2 ^{ \frac{1}{3} }.2 ^{ \frac{4}{3} }}{ (\frac{1}{8}) ^{-3}})=\\ \\ ( \frac{ 2 ^{2}.2 ^{ \frac{1}{3} }.2 ^{ \frac{4}{3} }}{ 8 ^{3}})=\\ \\ ( \frac{ 2 ^{2+ \frac{1}{3} + \frac{4}{3} }}{ 2 ^{9}})=\\ \\ ( \frac{ 2 ^{ \frac{11}{3}}}{ 2 ^{9}})=\\ \\ 2 ^{ \frac{11}{3}-9}}= \\ \\ 2^{ -\frac{16}{3} }")
Duvidas?! é só comentar
Duvidas?! é só comentar
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