Question

como se calcula esta inequação 6n

Answer 1

6 n  <n² + 8
n² + 8 >6 n
n² - 6 n + 8  >0
Δ = b² - 4 . a .c
Δ = (-6)² - 4 . 1 . 8
Δ = 36 - 32
Δ = 4 ⇒ √ 4 = 2
n = - b + ou- 2/2 .1
n = -(-6) + 2/2
n = 6 +2 /2
n = 8/2
n = 4
n = 6 - 2/2
n = 4/2
n = 2
 letra c)

Answer 2

Boa noite Eunice!

Solução!

$6n\ \textless \ n^{2}+8 \\\\\ n^{2}-6n+8\ \textgreater \ 0\\\\\\ Resolvendo a inequacao.\\\\\ a=1\\\\\ b=-6\\\\ c=8$

Formula de Bhaskara.

$n= \dfrac{-b\pm \sqrt{b^{2}-4.a.c } }{2.a}\\\\\\ n= \dfrac{-(-6)\pm \sqrt{(-6)^{2}-4.1.8 } }{2.1}\\\\\\ n= \dfrac{6\pm \sqrt{36-32 } }{2}\\\\\\ n= \dfrac{6\pm \sqrt{4 } }{2}\\\\\\ n= \dfrac{6\pm 2 }{2}\\\\\\ n_{1}= \dfrac{6+2}{2}= \dfrac{8}{2}=4\\\\\\ n_{2}= \dfrac{6-2}{2}= \dfrac{4}{2}=2\\\\\\ Como ~~a~~ funcao ~~e~~ maior ~~que~~zero~~ concluimos~~ que. \\\\\\ Resposta\\\\\\ S=\{n\in\mathbb{R}/ 2\ \textless \ n~~ou~~n\ \textgreater \ 4\}$


$\boxed{Alternativa~C}$

Boa noite!
Bons estudos!