Question

Como resover 3log16+2log8-6log4

Answer 1

Olá.

$3log16 + 2log18 -6log4 =$

$= 3log2^4 + 2log2^3 - 6log2^2$

$= log(2^4)^3 + log(2^3)^2 - log(2^2)^6$

$= log2^{12} + log2^6 - log2^{12}$

$= log\frac{2^{12}*2^6}{2^{12}}$

$= log\frac{2^{12+6}}{2^{12}}$

$= log\frac{2^{18}}{2^{12}}$

$= log{2^{18-12}$

$= log2^6$